C++, Plz explain this program logic to me

Question

Int* function (int* p){
P+=2;
Return p;
}
Int main(){
Int array[5]={1,2,3,4,5};
Int* ptr= array;
Cout<< *(function (ptr));
Return 0;
}

Answer 1

Int* ptr stores the address of first array element .

At line Int* function (int* ptr); //int*ptr accepts the address .

p+=2; // increments the address by 2*sizeof(int) =8 . If the initial address was 104 next address will be 112 (which will basically have array number 3 stored at it ) .

return p; // returns the address as the type of function is Int* .

At line *(function (ptr)) ; //* dereference the address and returns the value(3) stored at it

Answer 2

Nitin Bisht it is not a pointer to function . int* is the return type of function here like int, void, string type.

And if i am not wrong we can put a pointer to a function but that has a different syntax and i can't help with that.

Answer 3

Abhay can we put pointer to a function I have never face this type of program before ?
Int* function (int* p)