How to make this have a space between words

Question

import re
new_str = ""
user_str = input()
pattern = r'[^a-zA-Z]'
new_str = re.sub(pattern, '', user_str)
print(new_str[::-1])

This code takes a string from user, matches anything that isn't a letter, replaces it with an empty string, reverse, then prints it.
Problem is, it doesn't add a space between words, but meanwhile it works well for a two word sentence.

Answer 1

Just add a space to your pattern so they aren't removed.

r'[^a-zA-Z ]'

Answer 2

???? Why down vote I just told you your problem lol

Answer 3

ChaoticDawg thanks

Answer 4

if you add a space ' ' that will prevent removing only this specific space... if you want to add any kind of spaces (common ascii one, but also tabulations, new lines, non-breaking space, special unicode spaces of different widths...), you should use the '\s' (it's counterpart is '\S' wich means anything that is not a space):

pattern = r'[^a-bA-B\s]'

here the r prepending the string is useful, as you use backslash to escape the s in the regexp, but not in the string ;P

without, you need to escape it as well:

pattern = '[^a-bA-B\\s]'

and your pattern start to become less readable ;)

Answer 5

Roderick Davis i already knew the problem, now i have tried to dissolve it but i failed that's why i posted so you guys could help me out

Answer 6

Becuase spaces arent letters so they are removed