problem with swaping the numbers in c++

Question

int A{10};
int B{20};

int *num1{&A};
int *num2{&B};

int *temp{num1};
num1 = num2 ;
num2 = temp;

Here I have observed that *num1 and *num2 swapped but not A & B........
why??????

Answer 1

//Instead
Int *temp{num1};

//Use
Int *temp = num1;

Got idea from this link. Plz check it out
https://stackoverflow.com/questions/15672805/c-swapping-pointers

Hope it helps you