Why the heck is this not working??

Question

user_age = input()
if user_age != int:
print("Sorry, that is invalid.")
I'm using Pydroid and when I run the above code it returns Sorry, that is invalid every stinking time. I could not find anything helpful on the Internet.

Answer 1

Try this:

if user_age.isnumeric():
print("...")

Answer 2

--More about isnumeric() method--
The isnumeric() method returns True if all the characters are numeric (0-9), otherwise False.

Exponents, like ² and ¾ are also considered to be numeric values.

"-1" and "1.5" are NOT considered numeric values, because all the characters in the string must be numeric, and the - and the . are not.

Syntax-
string.isnumeric()

Answer 3

Take int as input
user_age = int(input())

Answer 4

6hpxq9 Yeah I got it, thanks :) Slowly learning 😅

Answer 5

Thanks! :)

Answer 6

Dea Mer Aside from other answers, You can also use the try-except statements to catch error in case the input cannot be converted to int (i.e. not an integer).

try:
user_age = int(input())
except:
print("Sorry, this is invalid")

Answer 7

Dea Mer You haven't assigned a value for variable int so all the time it say "Sorry, that is invalid"

Answer 8

You have to convert the input to int
I mean, if the var int is an integer :v

user_age = int(input())

It's a common error, don't worry ;)