Why it shows error

Question

https://code.sololearn.com/ciw66oJ5VHAa/?ref=app

Answer 1

See it's showing an error because u haven't defined 👉🏻(a).

So let us take👉🏻 (a=24)

Now u code will become as:

a=24
def func(a):
print(a)
a+=1
print(a)
print(a)
func(7)

Answer 2

'a' is a local variable means access to 'a' is limited to the scope where it was declared.

Here scope of 'a' is the function . you can only access 'a' within the function.

Trying to access it in outside of function giving you error on line 6

Answer 3

I tried inside still it shows error

Answer 4

Akash Prasad you have to create another variable outside function named 'a' .
https://code.sololearn.com/cLAukOluKbyJ/?ref=app

Answer 5

Global variable 'a' is not defined.

Answer 6

def func(a):
print(a)
a+=1
print(a)
func(7)
a is not a global variable