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# The code incorrectly calculates the sum of the digits of the number. For example, if you enter 157, then the output will be LOCK

6 Answers

+ 2

The problem is actually your second term bracket. You shouldn't and two numbers, because it will return True/False
(1 and 1) == True # True is also 1
so instead you can just remove the bracket and the and
c // 100 + c // 10 + c % 10 == 13:
however, the second term will be wrong, so you need to adjust it a bit
c // 100 + c // 10 % 10 + c % 10 == 13:
so let's say 157,
157 //10 = 15
15 % 10 = 5, which is the number you want
Another alternative and maybe easier way is to loop the string and plus the int of each character
c = input() # didn't convert to int here
total = 0
for char in c:
total += int(c)
And here is the standard way everyone getting the sum of tbe digits
c = int(input())
total = 0
while c > 0:
total += c % 10
c //= 10

+ 1

Polina Voqy
What do you expect and what are you doing here?
https://code.sololearn.com/cw6Cz4ogRgPk/?ref=app

+ 1

Thanks for the help

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It is lock. When you input number less than 100 and more than 999 then you'll got FALSE. If sum of digits of a number is 13 output is ENTER. In other occasions LOCK.
But when I write 157 or 247 and also some more, it outputs LOCK

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Thanks for the explanation

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