Club bouncer help

Question

Getting a line 5 syntax error at name in the if statement

age = int(input())
name = input()

If age>= 18:
print (“Welcome” name)
else:
print (“Sorry”)

Answer 1

Put a comma before name

Answer 2

print("Enter Your Name:")
name = input()

print("Enter your age :")
age = int(input())
if age >= 18:
print("You Are Allowed To Enter!", name)
else:
print("Sorry? You Are Not Allowed to Enter!", name)

Answer 3

Answer

age = int(input(""))
name = input("")

if age >= 18:
print("Welcome " + name)
else:
print ("Sorry")

Answer 4

you have to create variable for 18

age = int(input(""))
name = input(" ")
a = int(18)
if age>=a:
print("Welcome "+name)
else:
print("Sorry")

Answer 5

Please copy and paste the problem here
The question is unclear, even if I point out mistakes I will never know what was the code for
BTW, the error is here
print (“Welcome” name)
instead of that, write
print (“Welcome”, name)

Answer 6

Sheena I guess you forgot to concatenate the strings with a plus sign. Also, 'If' doesn't work.

Answer 7

Would be inevitable for me to scream from bottom of my heart "What a rocket science!'

Answer 8

age = int(input())
name = input()

If age>= 18:
print (“Welcome” name)
else:
print (“Sorry”)

Answer 9

Use this and it will work. Dont forget that you dont need to put plus between welcome and name, instead put comma.

age = int(input())
name = input()
# your code goes here
if age>= 18:
print("Welcome", name)
else:
print("Sorry")

Answer 10

This gonna work 😄 try it
age = int(input(""))
name = input(" ")
a = int(18)
if age>=a:
print("Welcome "+name)
else:
print("Sorry")