You are given a program that outputs all the numbers from 0 to 10. Change the code to make it output only the even numbers

Question

x = 0
while x<=10:
if (x % 2 = 0)
print(x)
x += 1

This is my code but it keeps on outputting 0

Answer 1

= is used for assignment of variables and values

== is used for comparisons

And also keep in mind the indentions and colons after if conditions.

if (x % 2 == 0):
print(x)

Answer 2

NWACHUKWU PRECIOUS CALEB

There should be == not =

x = 0
while x <= 10:
if x % 2 == 0:
print(x)
x += 1

Answer 3

(syntax error) you use ==

Code:
x = 0
while x <= 10:
if x % 2 == 0:
print(x)
x += 1

Answer 4

Change the = to == in the 3rd line. = is an assignment operator

Answer 5

x = 0
while x<=10:
if (x % 2 == 0):
print(x)
x += 1

The if statement needed a : at the end of the parenthesis. Indented everything correctly and the code worked for the solution.

Answer 6

x = 0
while x <= 10:
if x % 2 == 0:
print(x)
x += 1

make sure about the indentations that will provide you the error for this

Answer 7

X=0
While x<=10:
If x % 2==0:
Print(x)
What do I do next?

Answer 8

You are given a program that outputs all the numbers from 0 to 10.
Change the code to make it output only the even numbers.
Solve immediately

Answer 9

x = 0
while x <= 10:
if x%2 == 0:
print(str(x))

x += 1

Answer 10

x = 0
while x <= 10:
if x % 2 == 0:
print(x)
x += 1

Answer 11

Here is the correct answer

x = 0
while x<=10:
if x%2== 0:
print(x)
x+=1

Answer 12

correct answer

x = 0
while x<=10:
print(x)
x += 2

Answer 13

x = 0
while x<=10:
print(x)
x+=10
x-=8