Function Arguments

Question

Fill in the blanks to define a function that prints "Yes", if its parameter is an even number, and "No" otherwise.
____ even(x):
if x%2 == 0:
____ ("Yes")
________
print("No")

Answer 1

Attunuru Baby Sri Laya
else
print("No")

Answer 2

Attunuru Baby Sri Laya

I think you missed a colon

else:
print("No")

Answer 3

There i guess it would be else
Read the question well you will get your answer

" If it is even print yes **else** print no"

Answer 4

Attunuru Baby Sri Laya If you are talking about Quizzes in the lessons ,You can get the answers from the comments below in each quiz if u couldn't make it , Check that out !!!

Answer 5

Attunuru Baby Sri Laya, show your attempt please, we are not doing homework in the Q&A fourm.

Answer 6

@Dino Wun
def even(x):
if x%2==0:
print ("Yes")
_______
print("No")
##Actually i tried a lot to fill that place but i couldn't get it!!
If possible could u pls help me in solving it...!!!

Answer 7

@Krish @Alphin K Sajan
Yeah i tried it in first attempt only.....but it's incorrect.

Answer 8

@Krish
Yup.....Thanks