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# finding lcm in python

Hi friends. Can you please help me ? To practice, I want to write a program to find lcm . But my program has some problems and it doen't have any result. Thank you for helping me correct the problems. number_1 = input("Hello! Please enter your first number: ") number_2 = input("And your second number please? ") i = 1 j = 0 while j != i: n = 1 while j != i: i = number_1 * n n = n + 1 m = 1 while j != i: j = number_2 * m m = m + 1 else: print("lcm",i)

6 Answers

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I tried to run it too at the same time, but it still does not work because the both numbers are still multiplied by the same number (n)
For example:
num1 = 10
num2 = 20
n = 1
- - - - - - - - - - -
10 * 1 = 10
20 * 1 = 20
- - - - - - - - - - -
10 * 2 = 20
20 * 2 = 40
- - - - - - - - - - -
10 * 3 = 30
20 * 3 = 60
and so on..
And when this happens, the multiple of two numbers will never meet or intersect cause their gap or difference is getting larger and larger every loop (because they are multiplied by the same number).
However, you can use data structures like lists to append every factors and find then print the least common number of both list just like the LCM.
- - - - - -Another ways to solve LCM- - - - - -
1. You can solve first the GCD:
LCM = (num1 * num2) / GCD
2. You can also use modulo:
if x > y:
higher_num = x
else:
higher_num = y
if (higher_num % y == 0) and (higher_num % x == 0):
print("LCM =", higher_num)
else:
higher_num += 1
Najmeh I hope I helped somehow😊

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Nicko12 and Ratnapal Shende thank you for devoting your time and helping me

+ 3

First of all,
number_1 = int(input("text: ")
number_2 = int(input("text: ")
But it still doesn't work so wait a second, I'll figure out the rest.

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The problem is that
The second "while j != i" will never become True (because it just keeps multiplying the number_1 by n), therefore j and i will never be equal and it will cause an infinite loop and prevents the second "while loop" below it from running.

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# Najmeh you can run two loops simultaneously using multiprocessing module
from multiprocessing import Process
def loop_a():
while 1:
print("a")
def loop_b():
while 1:
print("b")
if __name__ == '__main__': Process(target=loop_a).start() Process(target=loop_b).start()
#Stack
#Google
http://docs.python.org/library/multiprocessing.html

+ 2

So how can I run the second and third loops at the same time?