Why does it give different answer for the following code?

Question

int num = 1;
int total = 0;
while (num <= 5)
{
cin >> num;
total += num;
num ++;
}
cout << "Total = " << total << endl;

return 0;
}

I entered five numbers which are 1, 7, 6, 8, 9
the answer should be 31 right
but why does it output total = 8

someone please help

Answer 1

your while loop is checking if num <= 5, when you enter 1, the first loop 1<=5, the second time you enter 7, then increment num, 7+1 = 8. 8 is not less than or equal to 5 so your loop exits and you get 8.
instead I think you might want a for loop.
try
int num = 0;
int total = 0;
for (int i=0; I <=5; i++)
{
cin >> num;
total += num;
}
cout << "Total = " << total << endl;

return 0;

that will let you enter 5 numbers and then add them together

Answer 2

yes I see, originally you had num used twice instead of number and num.
that cause you to check against the wrong variable. The latest post should work :)

Answer 3

sorry, updated it a little to remove the unnecessary parts for your basic example

Answer 4

thanks.
but I found out that when I use the code of c++ lesson which is -
int num = 1;
int number;
int total = 0;
while (num <= 5)
{
cin >> number;
total += number;
num++ ;
}
cout << " Total = " << total << endl;
return 0;
}

giving number 1, 7, 6, 8, 9
And
The output was 31

maybe i made syntax error by not writing
int number;
in the code of my previous question.

If so, please make me sure about that.

Answer 5

thank you