What will be the final value of variable sum?

Question

Line-1: #include<stdio.h>
Line-2: int main(){
Line-3: int cnt=1, sum=0, n=6;
Line-4: while(cnt<=n){
Line-5: sum=sum+cnt;
Line-6: ++cnt;}
Line-7: printf("average=%f", sum/6.0);
Line-8: return 0;}

Answer 1

Check in the code playground..!

Edit : if you don't understand what happening :
sum = 1+2+3+4+5+6 = 21
Output : 21/6.0=> average=3.5

Answer 2

to print the average of the sum of 1 to n you can use (n(n+1)/2)/n => (n+1)/2