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I want to count the words in a text

Hello! I want to count the words in a text, but I don’t know who to do it, can someone help me please, Thank you! https://code.sololearn.com/cr55uA6N8JV3/?ref=app

16th Nov 2020, 4:42 PM
Alejandra b
Alejandra b - avatar
9 Answers
16th Nov 2020, 4:49 PM
Pratyush Raj[LEFT]-TEMP
Pratyush Raj[LEFT]-TEMP - avatar
+ 3
print(len(input().split()))
16th Nov 2020, 8:52 PM
Yurii Ostapenko
Yurii Ostapenko - avatar
+ 3
Jayakrishna🇮🇳 If you assume that words can contain any digit/symbol, then in the example used by Ƥŕᥲ七Ꮍųꗟ♄ ℜᥲᒎ and also included in code of Alejandra b contains symbols like, , ? . So, I assume that OP is saying to omit these things. But, I may be wrong...
18th Nov 2020, 6:25 PM
777
777 - avatar
+ 2
first you must split the string, then get its length (number of items in an array) use these key words len() split()
16th Nov 2020, 8:02 PM
Logomonic Learning
Logomonic Learning - avatar
+ 1
#your way by function : txt = "Whatever Comes Out Of These Gates, We have Got A Better Chance Of Survival If We Work Together. Do You Understand? If We Stay Together, We Survive" def count_words(txt): count = 0 for i in txt.split() : count+=1 return count print(count_words(txt))
16th Nov 2020, 5:43 PM
Jayakrishna 🇮🇳
+ 1
# The `split` method wouldn't work if in case, the word is like, sentence = "I have 9 $ in my pocket - A guy" # In that case, you could use, import re matches = re.findall(r"[a-zA-Z]+", sentence) print(len(matches)) # If you want the whole list, then print(list(matches))
18th Nov 2020, 1:30 PM
777
777 - avatar
+ 1
Jayakrishna🇮🇳 You can do `count += i.isalpha()` instead of `count += 1`, to make it work in general!
18th Nov 2020, 1:36 PM
777
777 - avatar
+ 1
@vrintle Am not the questioner. May be wrong tag you added..!? But In your sentence 9, $, - are also counted as words until especially said to ommit. Raw Words may contains any special chars and digits..
18th Nov 2020, 3:59 PM
Jayakrishna 🇮🇳
0
print(len(txt.split()))
24th May 2021, 2:11 PM
Lucas Steven
Lucas Steven - avatar