Can someone please help with this ? Thanks

Question

def testFunc(x, y = []):
y.append(x)
return y

a= testFunc(1)
b= testFunc(2,[])
c= testFunc(3)
print(c)

Answer 1

Print(c) prints [1,3]

>To a* you assigned testFunc(1) here you have passed 1 as parameter to the testFunc(x,y=[]) ...empty list of y will be appended with 1 so ,we will have 1 in y like y=[1] will be returned.

>To b* you assigned testFunc(2,[]) passing 2 parameter with 1 empty list too so ,as we pass that empty list will be appended with 2 so this will return [2].

>To c* you assigned testFunc(3) and here you are passing only 1 parameter that's 3,we have y with 1 already so this 3 will be appended to that existing list containing 1,since you printed c .

It outputs [1,3]

Answer 2

a, b return not printed
c printed return [3]
[].append(3)= [3]