Printing characters in a while loop

Question

I've been trying to get a grasp of pointers but I'm not understanding one part when i try and print out characters seperately. It works, but i have no idea why adding brackets fixes my issue. I am trying to print out each string in a seperate line one character at a time.

Line 16 of my code shows a while loop printing out each character of the pointer array.

Why do i need the curly brackets? Without them, the '\n' character gets teated as if its in the while loop without any indentation or enclosing brackets. I threw an empty pair on there for laughs and it worked. Can anybody shed some light on why it acts like that?
https://code.sololearn.com/clfS8YSqkXjs/?ref=app

Answer 1

No. See don't have identation counting.. You can put any empty spaces in between 2 statements..
Other than python, most other languages treats semicolon as end of statement, and curved braces as blocks of Code..

Answer 2

Without braces, next statement is treated as belong loop..
You know for only single statement we don't need braces..

Answer 3

Considering the use of `putchar` return value as the while-loop condition, you can simply put a semicolon at the end of while-loop definition to tell the compiler that the loop doesn't have a loop body.

while(putchar(*(*(fruit+x)+y++)));

* Additional info for those who wonders why putchar is used in while-loop condition:

The `putchar` function returns the given character argument (promoted as int) on success, except for EOF, in which case `ferror` is set.

When the string terminator was given as argument (dereferenced from the char pointer), zero is returned - effectively stops the loop.

http://www.cplusplus.com/reference/cstdio/putchar/

Answer 4

Right, Jayakrishna🇮🇳 but even so does the indentation not matter?

Answer 5

Nice, i got it. Thanks

Answer 6

You're welcome..Slick