helpp!!!!

Question

import java.util.Scanner;
public class ascending
{
public static void main(String []args){
int i,j,min,t;
Scanner sc = new Scanner(System.in);
int m[] = new int[10];
for(i=0;i<m.length;i++){
System.out.print("Enter a no:");
m[i] = sc.nextInt();
}
for(i=0;i<9;i++){
min = i;
for(j=i+1;j<10;j++){
if(m[i]<m[min]){
min = j;
}
}
t = m[i];
m[i] = m[min];
m[min] = t;
}
System.out.println("Ascending order");
for(i=0;i<10;i++){
System.out.println(m[i]);
}
}
}

what's wrong in this code of printing ascending order using arrays in java??

Answer 1

https://code.sololearn.com/clOjB869nTHr/?ref=app
Sunita Zirange
your code

Answer 2

i am not getting my required output if u want to see wht output i have got then pls pls run by urself i am getting the same order as i have entered not an ascending order.......plsssss help!!

Answer 3

The easiest will be first sort
Arrays.sort(m);
and then print as above.

Answer 4

pls i need the program my friends are waiting for the answer.......at least give me a logic of it....

Answer 5

// if (m[ i ] < m[min]) {
if (m[ j ] < m[min]) { // not i
min = j;
}

Answer 6

import java.util.*;
public class ascending
{

public static void main(String args[]){
System.out.println("Enter numbers");
Scanner keyboard = new Scanner(System.in);
int[] m = {1,5,3,7,8,2,4,6,9};
/*for(var I=0;I!=10;I++){
m[i]=keyboard. nextInt();
}*/
Arrays.sort(m);
System.out.println(Arrays.toString(m));
}
}

Answer 7

thank you very much zemiak and moges ...i will never forget you!!
thanks a lot! :) :) :) :) :)

Answer 8

ok moges, i got it u have put both the values one is input by user and second is u have initialised it .....ok nothing ur program is absolutely correct!!