Printing messages when there is no input

Question

Is there a way I can add

if User_input1>=int(1001):
print("Input must be less than 1000")

And

if User_input2>=int(251):
print("Input must be less than 250")

To this code and make it work, or get similar results? I’ve tried some variations not using try/except and some of them print only the first message or print both the input and the message.

User_input1=input()
if not User_input1:
print("Please enter first value")
else:
print(User_input1)
try:
User_input2=input()
print(User_input2)
except:
print("Please enter second value")

Answer 1

An empty string is falsey in python, so just use;

if User_input1:
as
if not User_input1:

Is an empty string you're negating it to true and if true making it false.

You can also substitute a value during input if nothing is entered using;

User_input1 = input() or value

If input() results in an empty string then the value is returned to User_input1

Remember the input value will be of type string so if you're needing an int type then you need to convert to int().

if int(User_input1) >= 1001:
...
if int(User_input1) >= 251:
...