Explain me this code please

Question

#define sqr(X)X*X

Int X=16/sqr(4);

printf ("%d",X);

Why it's answer is 16??

Answer 1

#define replaces every instance of sqr(X) with X*X.

So following this :-

16/sqr(4)
Is replaced by
16/4*4
And by *BODMAS* it solves to 16

Hence the output is 16

Answer 2

Got it bro thanks ☺️