How to code "How many vowels in this strings"

Question

I'm a novice about Python.
I tried to code "Count how many vowels in this strings"

There is a way I can code, but it's so messy so I wanted to make it simple.

Below is the problem that I have to solve.
""" Write a program that counts up the number of vowels contained in the string s. Valid vowels are: 'a', 'e', 'i', 'o', 'u' . For example, if s ='ffsdfddadxcxvxaaed', your program should print >>> Number of vowels: 4

So below is code that I coded.

---------------------------------------------
s = 'dfsjknsckmlaaeiodkldmf'

for i in s:
vowels = 0
if i == 'a':
vowels += 1
else:
pass

print(vowels)
--------------------------------

When I run this, the result is 0.

My question is,
1. why my coding result is 0? And what is wrong with my code?
2. How can I code simply about "How many vowels in this strings?"

Thank you for making time and I hope you to have really great days!! :):):)

Answer 1

using list:

text = input()
my_list = ["a", "e", "i", "o","u"]
new_list = []
for c in text:
if c in my_list:

new_list.append(c)

print(len(new_list))

Answer 2

text = input()
count = 0
vowels = ["a", "e", "i", "o", "u"]
for x in text:
if (x in vovels):
count += 1

print(count)

Answer 3

Try this. This works.

str = input()
count = 0

for c in str :
if(c=='a' or c=='e' or c=='i' or c=='o' or c=='u' or c=='A' or c=='E' or c=='I' or c=='O' or c=='U'):
count += 1

print(count)

Answer 4

전민경 Because you are re-initialise the vowels variable inside loop. That's why your result is giving 0.
It should be like this:

string = "abcdaefghaj"

vowels = 0

for i in string:
if i == 'a':
vowels += 1

print(vowels)

Answer 5

Thank you so much! I did such a baby mistake uuuu Thanks a lot have a nice day!!

Answer 6

Here is my solution ,i think this is more shorter than what was posted here :

string=input()
count=0
for c in string :
if c in {"a","e","i","o","u"}:
count+=1
print(count)

Answer 7

Here is my solution:
text = input()
my_list = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U",]
i = 0
for ch in text:
if ch in my_list:
i += 1
print(i)

Answer 8

str = input()
count = 0

for c in str :
if(c=='a' or c=='e' or c=='i' or c=='o' or c=='u' or c=='A' or c=='E' or c=='I' or c=='O' or c=='U'):
count += 1

print(count)

Answer 9

print(len([x for x in input().lower() if x in ["a","e","i","o","u"] ]))

Answer 10

Here is the code i tried but it keeps given me 0
string = ()

vowels = 0

for i in string:
if i == 'a':
vowels += 1

print(vowels)

Answer 11

Simisola Osinowo You forgot to add 'input' at the beginning of your code.
---
string = input()
---

Also, you might want to include all the vowels and use 'in' instead of '=='.
---
if i in 'aeiou':
---

https://code.sololearn.com/cEBgsEN1Vw37/?ref=app

Answer 12

Vowels program making

#your code goes here
s = str(input(''))

vowels = 0
for i in s:

if i == 'a':
vowels += 1
if i == 'e':
vowels += 1
if i == 'u':
vowels += 1
if i == 'ü':
vowels += 1
if i == 'o':
vowels += 1
if i == 'ö':
vowels += 1
if i == 'ı':
vowels += 1
if i == 'i':
vowels += 1
else:
pass

print(vowels)

Answer 13

sample_text = input()
vowels = "aeiou"
total = 0

for letter in sample_text:
counter = 0
while letter != vowels[counter]:
counter += 1
if counter == 4:
break
if letter == vowels[counter]:
total += 1

print(total)

Answer 14

string = input()
vowels = 0
for i in string:
if i == 'a' or i=='e' or i=='i' or i=='o' or i=='u':
vowels += 1
print(vowels)

Answer 15

x = input('enter a string:')
v=['a', 'e', 'i', 'o', 'u']
s=0
for c in x:
for l in range (0, len(v)):
if c==v[l]:
s+=1
print(s)

Answer 16

x = input('enter a string:')
v=['a', 'e', 'i', 'o', 'u']
s=0
for c in x:
for l in range (0, len(v)):
if c==v[l]:
s+=1
print(s)

Answer 17

This is my code:

n = str(input())
from collections import Counter

counter = Counter(n)
a=(counter['a'])
e=(counter['e'])
i=(counter['i'])
o=(counter['o'])
u=(counter['u'])
print(a+e+i+o+u)

OR SIMPLER:

n = str(input())
a=(n.count('a'))
e=(n.count('e'))
i=(n.count('i'))
o=(n.count('o'))
u=(n.count('u'))
print(a+e+i+o+u)

Answer 18

text= input()
a=text.count('a')
e=text.count('e')
i=text.count('i')
o=text.count('o')
u=text.count('u')
cont=a+e+i+o+u
print(cont)

Answer 19

#your code goes here
z = "aeiou"

y = input()
b=0
for i in y:
if i in z:
b +=1
else:
repr(b)

print(b)

Answer 20

string=input()
count=0
for c in string :
if c in {"a","e","i","o","u"}:
count+=1
print(count)