How can I print indexes number of a given number in the list?

Question

L=[1,3,8,3,12,3]
X=3
output:1 3 5

Answer 1

for i,j in enumerate(L):
if j==X:
print(i)

Answer 2

If you like to have the indexes found stored in a list, you can do like this:

L=[1,3,8,3,12,3]
res = [ind for ind,num in enumerate(L) if num == 3]
print(res) #output: [1, 3, 5]

Answer 3

L.index[3]

or
x=len(L)
for I in range(x):
if L[I] ==3:
print(I)

Answer 4

and use this to print all in the same line
print(i ,end="")
Out put:
1 3 8 3 12 3

Answer 5

You can make a loop to iterate from 0 to list length.

In each iteration you check if the wanted item is located at the index, which is the iteration number.

If it is, print the iteration number.

Answer 6

I do that but it he print 1 11 -->the first index

Answer 7

I want the indexes 3 in list

Answer 8

L=[1,3,8,3,12,3]
X=int(input())
for i in L:
if x==i:
Print(L. index(I))

Answer 9

It print
1
1
1

Answer 10

Thanks olivia it's work 😘

Answer 11

Your welcome 😀

Answer 12

for i in range(5):
if L[i]==value:
print(i)

Answer 13

L=[1,3,8,3,12,3]
for i in L:
print(i)
out put:
1
3
8
3
12
3