How can I make this code shorter ?

Question

Code for simplifying fractions

import java.util.Scanner;

public class SimplifyingFractions {
public static double smaller(double refer1,double refer2) {
if(refer1<=refer2) {
return refer1;
}
else {
return refer2 ;
}
}
public static void main (String[]args){
Scanner ask = new Scanner(System.in);
double a,b ;
a = ask.nextDouble();
b = ask.nextDouble();
double x = smaller(a,b);
do {
if(x !=1 && x==a && a%b==0 && a/b - Math.floor(a/b)==0) {
int Ia,Ib;
Ia = (int) a;
Ib = (int) b ;
System.out.println("(1) "+Ia/Ib);
break;
}
else if(x !=1 && a<b && a%x==0 && b%x==0 && a/x-Math.floor(a/x)==0 && b/x-Math.floor(b/x)==0) {
double r1,r2 ;
r1 = a/x;
r2 = b/x;
int Ir1,Ir2;
Ir1 = (int) r1;
Ir2 = (int) r2;
System.out.println("(2) "+Ir1+"/"+Ir2);
break;
}
else if (x==a && a%b!=0 && a/x-Math.floor(a/x)!=0 && b/x-Math.floor(b/x)!=0) {
int Ia,Ib;
Ia = (int) a;
Ib = (int) b ;
System.out.println("(3) "+Ia+"/"+Ib);
break;
}
}
while(x<=a || x<=b) ;
}
}

Answer 1

@AJ Anant #19 Sep End Day
I want to simplify fractions.
The first condition in the loop is for improper,properly divisible fractions like 4/2(outout will be 2)
The second condition is for simplifying proper fractions like 68/100 (output will be 17/25)
The third condition is for proper fractions that can not be simplified like 3/7

Answer 2

instead smaller() use Math.min()
// double x = smaller(a,b);
double x = Math.min(a,b);

but do {} while there is infinity loop
because x,a,b are not changed inside it

I try "5.25 8.75" as input for double variables

Answer 3

@zemiak
Thanks
I'm a beginner .I understand that I need to use Math.min() but I don't understand the second point.

Answer 4

https://code.sololearn.com/cPRXSt9k8rRZ/?ref=app

Answer 5

What you want to do here?

Answer 6

if none of the if () expressions are true, the program never terminates

Answer 7

zemiak Thanks