**New course!**Every coder should learn

**Generative AI!**

+ 3

# Operator Precedence

What is the answer for this: What is the result of this code? x = 4 y = 2 if not 1 + 1 == y or x == 4 and 7 == 8: print("Yes") elif x > y: print("No") i understand up to part 7==8.And then i don't understand what happen and what to do after print("Yes").I don't get it and what is the answer?

2 Answers

+ 2

First of all we have three conditions :
1+1==y [y=2]
1+1==2
Hence this statement is True
x==4 [x=4]
4==4
This is also True
7==8
This is False
So our condition
not 1 + 1 == y or x == 4 and 7 == 8
is now
not True or True and False
Now according to operators precedence:
1.Arithmetic operators[already solved above]
2.not
3.and
4.or
Now evaluating it
not True or True and False
False or True and False
False or False
False
Hence if condition is false andelif is true because x>y
therefore answer will be No.
I Hope this helps🙂🙂

0

x = 4
y = 2
Let's break down the conditions :
1+1 == y # True. Because 1+1 = 2 and y is also 2. So 2 == 2 is True
However adding 'not' in front of True makes it false. So
not 1+1 == y # False
As it is false it moves forward and check the next condition. The next condition is :
x == 4 and 7 == 8
x == 4 is True but 7 == 8 is false. And know we know operator 'and' returns true only if all the condition is true. We can see that one condition is True and the second one is False. Therefore
x == 4 and 7 == 8 # False
And hence
not 1+1 == y or y == 4 and 7 == 8 # False
That is why 'Yes' doesn’t get printed. However we let's move forward.
x > y # True. Because 4 > 2
As a result we get 'No' as output.