Tell me the Output of the code please

Question

import java.util.Scanner;

class MyClass {
public static void main(String[ ] args)
{

Scanner myVar = new Scanner(System.in);
int age =myVar.nextInt();
System.out.println(age);

if (age < 16)
{
System.out.println("Too Young");
}
else {
System.out.println("Welcome!");
}
}
}

Answer 1

It is JavaScript?

Answer 2

It is Java and not JavaScript.
You cannot have a variable name with space in between. So 'my var' is not a valid name, instead you could use 'myVar'. Also if you want to take an integer input then you must write-

int age = myVar.nextInt();

Answer 3

There are errors on your program

•name of your scanner should not have spaces.
•you did not declare variable age.
•my var.nextLine(); should be age=myvar.nextInt(); because you are pertaining to the age.
•because it's a user input type you can't tell the output unless you have constant value for age.

Answer 4

It is not JavaScript its Java,
There are some errors in the code :-

1) The "my var" is not valid it must be without space "myvar"

2) You must add "int age = myvar.nextInt();" before if statement.

3) After above given changes the "System.out.println(myvar.nextInt());" will cause error, change it to "System.out.println(age);" and type it after declaration of variable age.

And you can't tell the output before the user input.

Answer 5

//This is the code without errors :

import java.util.Scanner;

class MyClass {
public static void main(String[ ] args)
{
Scanner myVar = new
Scanner(System.in);
int age =myVar.nextInt();
System.out.println(age);
if (age < 16)
{
System.out.println("Too Young");
}
else {
System.out.println("Welcome!");
}
}
}

Answer 6

@Avinesh not working bro can you help me

Answer 7

King Aap This should be your first 3 lines.

Scanner myVar = new Scanner(System.in);
int age =myVar.nextInt();
System.out.println(age);

Answer 8

Ya

Answer 9

Avinesh thank you for your help
It's working now

Answer 10

@Avinesh
8
8
Is to young
Program finished