Java Array

Question

int result = 0;
for (int i = 0; i < 5; i++) {
if (i == 3) {
result += 10;
} else {
result += i;
}
}
System.out.println(result);

//output 17

1. Can someone explain to me the mechanism of this code?

Answer 1

It's easy.

Here i start with 0 so on first iteration if condition will not satisfy because i == 3 means 0 == 3 is false. So it will go in else condition where result = result + i means result = 0 + 0 = 0.

Same for i = 1, 1 == 3 false so result = 0 + 1 = 1

for i = 2, 2 == 3 false so result = 1 + 2 = 3
for i = 3, 3 == 3 true so result = 3 + 10 = 13
for i = 4, 3 == 4 false so result = 13 + 4 = 17

Answer 2

i = 0 then result = 0+0 = 0
i = 1 then result = 0+1 = 1
i = 2 then result = 1+2 = 3
i = 3 inside if => result = 3+10 = 13
i = 4 then result = 13+4 = 17
// output = 17

Answer 3

faakeer To understand mechanism just do like this. Here result += i means result = result + i.

int result = 0;

for (int i = 0; i < 5; i++) {
System.out.println("i = " + i);
System.out.println(i == 3);

if (i == 3) {
result += 10;
System.out.println("--if part--" + result);
} else {
result += i;
System.out.println("--else part--" + result);
}
}

Answer 4

thanks #AJ and #Shruthi let me try.

Answer 5

#AJ thanks for clarifying me great explanation 👏👏👏

Answer 6

AJ Anant ok genius 🤙

Answer 7

faakeer use @ before name to tag someone.