What is the output of this code?

Question

a = [0,1,2,3]
for a[-1] in a:
print(a[-1])

Answer 1

So

a = [0,1,2,3]

is the list

what for loop does in

for i in a:
print (i)

is that it assigns each values of a to i (or you can say iterates through a)

and prints
0
1
2
3

But here it is

for a[-1] in a:
print(a[-1])

So for the first time
a[-1] = 0
a = [0,1,2,0]
So 0 is printed because it will print the last element of the list.

For second time

a[-1] = 1
a = [0,1,2,1]
so 1 is printed

Third time

a[-1] = 2
a = [0,1,2,2]
so 2 is printed

But for the third time
a[-1] = 2 because the last element has now become 2
a = [0,1,2,2]
so 2 is printed again.

In the end output is
0
1
2
2

And the loop is ended here.

You can check this by putting print(a) in the loop.

Answer 2

UraL

Answer 3

Utkarsh Sharma very good

Answer 4

In the end output is
0
1
2
2

// a = [0,1,2,3]
for a[-1] in a:
print(a[-1])

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