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Functions assigned and reassigned to variables, and later referenced by those names: doubt

======================================= def multiply(x, y): return x * y a = 4 b = 7 operation = multiply print(operation(a, b)) ============================= The code above is an example given in the "Functions as objects" lesson. My question is: what exactly is "operation"? Is it a variable? Is it a pointer? Did it duplicated the multiply function? I know that I can treat it as a normal variable and do something like operation = 22 print (operation) >>>22 and as expected, print (operation(a, b)) no longer works. Thanks in advance!

14th Feb 2017, 2:09 AM
Rodrigo
Rodrigo - avatar
2 Answers
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It is a variable that references the existing function.
14th Feb 2017, 2:32 AM
Daniel W.
Daniel W. - avatar
+ 1
Imo, in pythin, variables only contain pointers. For example, >>>a = [1, 2] >>>b = a >>>a[0] = 3 >>>print(b) [3, 2] this happens. I think it looks like how pointer work in C.
15th Feb 2017, 4:41 PM
Sungmin Woo
Sungmin Woo - avatar