Need an explanation about the output

Question

Why is the answer [0,1]?
What is the output of this code
def f(x, a = []):
for i in range (x):
a.append (i * i)
print (a)
f(2)

Answer 1

2 is passed as argument to the function f

a = [] is an empty array

In the loop i takes values 0 and 1

0*0=0 is added to the array
1*1=1 is added to the array

The array is printed [0,1]

Answer 2

Ok,you function print an array that we each time add to its end the multiplication of numbers betwen 0 and 1 bythemselves.
The first iteration i=0 so i*i=0*0=0 so we add 0 to our array a[] .
The second iteration : i=1 and 1*1=1 we add 1 to the end of the array a so a becomes a=[0,1]
Remark that we dont arrive to 2 because Range(2) stops at 1

Answer 3

Thank you guys ♥️

Answer 4

Oh, sorry I got that

Answer 5

One more question isn't append about adding to the list, why in this case it goes after a.

Answer 6

You're welcome.

Answer 7

Not sure what are you asking.
a = [] is empty
a = [0] after we add/append 0 to list
a = [0, 1] after we add/append 1 to the list