Why doesn’t std::cout print?

Question

#include <iostream>

using namespace std;

int disassemble8080(int programCounter, unsigned char* codeBuffer)
{
short OPsize = 1;
switch(codeBuffer[programCounter])
{
case 0x00:
cout << "NOP\n";
break;
case 0x01:
cout << "LXI B " << codeBuffer[programCounter + 0x02]
<< codeBuffer[programCounter + 0x01];
OPsize = 3;
break;

}
return OPsize;
}

int main()
{
unsigned char myCodes[10]= {1, 34, 12};
disassemble8080(0, myCodes);
cout.flush();
return 0;
}

This doesn’t print anything, even after cout::flush

Answer 1

Coder Kitten Gregor Dietrich i found the solution. so basically the unsigned char was being interpreted as the corresponding ascii code when I wanted it to be an integer. I fixed this by casting the print to print the integer version of the unsigned char. I am worried that the cast will increase the size of the 1 byte integer, because the system that I am emulating only works with unsigned char.

Answer 2

I've never even heard of the flush() method, you probably don't need it.

best bet would be that your switch cases are never triggered.
are you sure codeBuffer[programCounter] evaluates to 0x00/0x01?

try putting a

cout << codeBuffer[programCounter];

right at the beginning of your disassemble8080() function and see what you get.

Answer 3

maybe I missed something but 1 is generally not the same as 0x01