I don't know how to solve this problem."n" numbers are given.These must be displayed in ascending order after the last digits. | Sololearn: Learn to code for FREE!
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I don't know how to solve this problem."n" numbers are given.These must be displayed in ascending order after the last digits.

"n" numbers are given.These numbers must be displayed in ascending order after the last digit of the number. I tried to solve this,but i can't finish it. Can you help me? C++ https://code.sololearn.com/cR2IU8LfzgvL/?ref=app

28th Oct 2019, 3:47 PM
George Listru
George Listru - avatar
7 Answers
+ 4
for(i=0;i<n-1;i++){ for(j=i+1;j<n;j++{ m=arr[i],n=arr[j] for(int k=1;k<=(max_lengthBetween(arr[i],arr[j]));k++){ /* compare last digit of m,n using %10 & change value of m,n by /10 (removing their last digit), if last digit of m is less than last digit of n, then replace value of arr[i] & arr[j] and break; from this inner loop */ } } } //purpose of max_lengthBetween(arr[i], arr [j]) is to handle elements with different lengths like 234, 1234 here 1234>0234 as 1>0
28th Oct 2019, 5:21 PM
Gaurav Agrawal
Gaurav Agrawal - avatar
+ 2
Input: 3 - that means that only 3 numbers are allowed to be used, but i can write 6,12 if i want. 2313 241 712-these are the numbers. Output: Because the last digit of 2313 is the hightest, it will be displayed first. After- 712 and then 241 So the output will be diaplayed like that: 2313 712 241
28th Oct 2019, 4:16 PM
George Listru
George Listru - avatar
+ 2
till line 13th program seems to be correct(taking input correctly), after that it looks like you are trying to use selection sort so you need 2 loops for it, but inside that inner loop you need another loop for comparing last digits(like in 243 & 253, we can't sort by just looking at 3, we need to look next last digit 4,5 also) and using it swap values in array.
28th Oct 2019, 4:35 PM
Gaurav Agrawal
Gaurav Agrawal - avatar
+ 1
George Listru Can you give an example of what input is given and what output is expected? Is this related with the previous problem? I thought you already solved it.
28th Oct 2019, 4:09 PM
Ipang
+ 1
I do not understand very well because I do not speak native English. Can you show me in the program?
28th Oct 2019, 5:08 PM
George Listru
George Listru - avatar
+ 1
George Listru Making a progress? it's pretty quiet here. Just came to confirm something. So the number of digits in each input number doesn't matter, we just sort them by their last digit in descending order. Is this really how it is supposed to work? but what if one of the numbers were negative? what then? For example, 4 samples: 542, 713, 420, -821 Should the output be like this: 713 542 420 -821
29th Oct 2019, 9:43 AM
Ipang
0
I got a lot of errors, can you insert this in my program so i can see better?
28th Oct 2019, 5:38 PM
George Listru
George Listru - avatar