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+ 3

# Armstrong Number could anyone break this down elaborately?

r = n%10; c = r*r*r; sum = sum + c; n= n/10;

1 Answer

+ 6

You did not initialize your variables...
Assuming that r, n, c, and Sum are integers...
r was assign to the value of the remainder of the division of n to 10.
c was assigned to the value of r to the power of 3
sum is assign the the initial sum value plus the value of c
Lastly, n is assign to the value of initial value of n that is divided by 10