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Can somebody tell me why in the code

while (currentRight < array.length - 1)... Why is it currentRight less than array.length -1. When the element we are searching for can be present in the index .. array.length-1. https://code.sololearn.com/cpkgTT33biXc/?ref=app

6th Sep 2019, 10:52 AM
stephen haokip
stephen haokip - avatar
1 Answer
+ 1
I think it has to do with the calculation of currentRight: currentRight = Math.min(array.length - 1, currentRight + jumpLength); jumpLength is 3. currentRight is 0. inside while loop: Min (8, 0 + 3) = 3 Min (8, 3 + 3) = 6 Min (8, 6 + 3) = 8 8 == array.length - 1 -> the while condition gets false -> break the loop now you can jump into the linear search and get 35 as output. while (currentRight < array.length) would return true because 8 < 9 is true. You would do the loop again. currentRight = Min (8, 8 + 3) = 8 if (array[currentRight] >= target) { break; } array [8] >= 35 returns true. the loop would break here. So while (currentRight < array.length - 1) prevents an unnecessary execution of the loop. I hope it helps :)
6th Sep 2019, 9:28 PM
Denise Roßberg
Denise Roßberg - avatar