What's the output of this code AND WHY? EXPLAIN PLEASE

Question

void func (int &x) {
int x= 5;
}
int main ()
{
int x =2
func (x)
cout x;
}

Answer 1

Output is 5 because function's "func" argument is of reference type (int &x). So that means it will be working with the exactly same variable x you declared in main function. So it sets x = 5 and x stays that way