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# Evaluate the following expressions

a=7 b=5 a%=3 z=(a>b)?a:b z=(b=2)+a++ - - a y=pow(a, 2)+sqrt(b*b) Please help guyz .Anyone online help this is urgent

2 Answers

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a%=3 sets a = 1
z=(1>5) sets z = 5
z=(5=2)+a++ = sets b to 2, then adds to it the value of a, ignoring the ++, the ++ will add the value in the next statement of the code. if it was ++a the value would change immediately. then you minus negative a, double negative makes it into + a, the ++ now changes the value of a making z = (b=2) + a++ (b now equals 3) - -a(the ++ now comes into affect and b = 5)
Lastly,
y = pow(2, 2) = 4 + sqrt(2*2) = 2
4+2 = 6

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Thanx