Why showing Match 2 while there 'A' is exists in string.

Question

import re

pattern = r"[^A-Z]"

if re.search(pattern, "this is all quiet"):
print("Match 1")

if re.search(pattern, "AbCdEfG123"):
print("Match 2")

if re.search(pattern, "THISISALLSHOUTING"):
print("Match 3")

Output
Match 1
Match 2

Answer 1

"pattern" tells that some match is found if some not-capital character is present: that's the case of Match1 and Match2.
If you want to see all matching characters, you can use findall():
https://code.sololearn.com/c932mkueVaai/?ref=app

Answer 2

There are non-capital alphabets and numbers in the second option.