What's the output of this code? ["AND WHY"]

Question

int x = 0 ;
int a [] = {3, 4} ;
a [x] = ++x ;
cout << a [0] ;

Answer 1

Oh, JavaScript is so different from C++. Thanks for correcting me, I thought the way they deal with arrays is the same.

@Potto I don't know C++. I completed the course but forgot everything the next day.

Answer 2

x is 0, so a[x] is ++x which means a[0] = 1. The answer is 1.

Answer 3

@Robobrine what? How is it not like that? The answer is 1.

Answer 4

int x = 0 ; /* initializing a variable x with 0 */
int a [] = {3, 4} ; /* initializing an integer array a with the values 3 and 4. The array automatically has the length two because there are two values in the curly brackets */
a [x] = ++x ; /* see my other comment, x[0] is the first value in the array (3), a[1] the second (4) */
cout << a [0] ; /* gives out the first value of the array */

Answer 5

The programm looks at the whole line:
a[x] = ++x;
First thing it does is the ++x. x was 0 before, so the line above turns into:
a[1] = 1;
a[0] doesn't change and stays 3.

Answer 6

Robobrine is right. Run it through your compiler, cheeze!

Answer 7

cheeze that's not how it works...

Answer 8

guys I'm so sorry can anyone explain the code line by line for am so confused with "arrays" specialy when I put the variable

Answer 9

when put the variable x into the [] of the array

Answer 10

@cheeze the code doesn't get executed left to right, it will first calculate ++x and then look at the rest, so you have a[1] = 1; not a[0] = 1;