Why the ans is 2.0 not 2.5. Please explain me the logic behind the output.

Question

Question:
what is the output
int a=5;
int b=2;
double result=(double)(5/2);
System.out.print(result);

Ans is 2.0
Explain the logic behind it
https://code.sololearn.com/coNpCo4Mejwu/?ref=app
https://code.sololearn.com/coNpCo4Mejwu/?ref=app

Answer 1

Ayush Pandey Chriptus actually explained it in his earlier reply. When you do

5/2

, integer division takes place. 5 is divided by 2 to give 2 (with remainder of 1). The result of the division is 2.

The resulting value is the casted to double, which is 2.0

Answer 2

If you look at the operator precedence table,

http://www.cs.bilkent.edu.tr/~guvenir/courses/CS101/op_precedence.html

Unary type cast has higher precedence compared to division operator.

(double)5/2 should be interpreted as ((double)5)/2, which should give you 2.5. I compiled your code using javac 1.8.0_191, and received result of 2.5. Can you show us the full code which gives you 2.0, or is this a challenge question? Are you sure you memorized the challenge details correctly?

Answer 3

Chriptus13 sir I dont need alternate option I wanna know logic behind it

Answer 4

Fermi and Chriptus13 Now I have corrected the question sorry for the inconvinence.Please explain me.

Answer 5

My answer applies to this aswell if you want to obtain 2.5 you need to cast one of them to double first, eg:

// double result = ((double)5)/2;

Or, you can also multiply one by 1.0

// double result = (double)(5*1.0/2)

Answer 6

Since 5 and 2 are ints the division will give u 2 without the rest and therefore when casting to double you get 2.0