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Technical interview question

Assume you have two tables in a relational database, one named BOOK and one named AUTHOR. There is a column in BOOK named author_id that references the AUTHOR table. The idea here is that a single author may have written multiple books. Write a SQL query that produces a result similar to this: Author Name total_books ----------- ------------- Charles Dickens 23 Dr. Seuss 51 Norman Mailer 20 Harper Lee 1 My answer: Select A.author_name, count(B.total_books) From Author A Left Join Book B on A.author_id = B.author_id;

17th Feb 2019, 12:34 AM
Jayne Thomas
Jayne Thomas - avatar
7 Answers
+ 5
Your results would look like this Author Name books written ----------- ------------- Charles Dickens 95 With COUNT() you must use GROUP BY "A.author_name" should be just "A.name" since it's located in "author" table. "A.author_id" should be just "A.id" for the same reason. And I don't understand where does the "total_books" come from. SELECT A.name, count(B.id) FROM Author A LEFT JOIN Book B ON A.id = B.author_id GROUP BY A.name;
17th Feb 2019, 1:15 AM
Toni Isotalo
Toni Isotalo - avatar
+ 1
Number of Books You are working on the library database, which contains the Books and Authors tables. Columns of the Books table: id, name, year, author_id. Columns of the Authors table: id, name. Write a query to get the author names and the number of books they have in the Books table. Note that some authors do not have any books associated with them. In this case, the result needs to include their names and have 0 as the count. The count column should be called books in the result. level Sort the result by the number of books, from highest to lowest. ???????????????????????
17th Sep 2023, 1:51 AM
Akrem Ammari
Akrem Ammari - avatar
+ 1
Number of Books You are working on the library database, which contains the Books and Authors tables. Columns of the Books table: id, name, year, author_id. Columns of the Authors table: id, name. Write a query to get the author names and the number of books they have in the Books table. Note that some authors do not have any books associated with them. In this case, the result needs to include their names and have 0 as the count. The count column should be called books in the result. level Sort the result by the number of books, from highest to lowest.
17th Sep 2023, 1:51 AM
Akrem Ammari
Akrem Ammari - avatar
+ 1
Assume you have two tables in a relational database, one named BOOK and one named AUTHOR. There is a column in BOOK named author_id that references the AUTHOR table. The idea here is that a single author may have written multiple books. Write a SQL query that produces a result similar to this: Author Name total_books ----------- ------------- Charles Dickens 23 Dr. Seuss 51 Norman Mailer 20 Harper Lee 1 My Answer: SELECT A.author_name AS "Author Name", COUNT(B.author_id) AS "Total Books" FROM AUTHOR A LEFT JOIN BOOK B ON A.author_id = B.author_id GROUP BY A.author_name ORDER BY "Total Books" DESC;
3rd Oct 2023, 1:50 PM
Shahorier
Shahorier - avatar
+ 1
select books.name ,year , Authors.name as author from books , Authors where Authors.id = books.author_id order by Authors.name, year asc;
6th Dec 2023, 6:27 AM
charudatta wagh
charudatta wagh - avatar
+ 1
SELECT Authors.name , COUNT(Books.id) AS books FROM Authors LEFT JOIN Books ON Authors.id = Books.author_id GROUP BY Authors.id, Authors.name order by books desc; this code gives the required output for solution but why I am getting test case failed ?
19th Dec 2023, 1:55 AM
Nomini Adimulam
0
Number of Books You are working on the library database, which contains the Books and Authors tables. Columns of the Books table: id, name, year, author_id. Columns of the Authors table: id, name. Write a query to get the author names and the number of books they have in the Books table. Note that some authors do not have any books associated with them. In this case, the result needs to include their names and have 0 as the count. The count column should be called books in the result. Sort the result by the number of books, from highest to lowest CODE : SELECT Authors.name, COUNT(Books.id) as books FROM Authors LEFT JOIN Books ON Books.author_id=Authors.id GROUP BY Authors.name ORDER BY books DESC;
12th Jan 2024, 6:21 AM
KS Sreniketh
KS Sreniketh - avatar