I get time limit exceeded .butexpecting output is" true and no of matched parenthesis " and false if parenthesis are not mathed

Question

def srr(s):

f=[]
for i in range(0,len(s)):
if s[i]=="(":
f.append(s[i])
for j in range(0,len(s)):
if s[j]==")":
f.append(s[j])
if len(f)%2==0:
k=0
d=0
while k<len(f)/2:
if f[k]==f[-(k+1)]:
k=k+1
d=d+1
return (True,d)
else:
return False
print(srr("g(f)(b)"))

Answer 1

Pay attention to while loop. And return in your variant always will give False. Because f[k] = ( and f[-(k+1)] = ), but ( and ) can not be similar. i want say '(' != ')' -> true.
https://code.sololearn.com/cCAERTBo8G2C/?ref=app

Answer 2

Please save it as a code so we can run it and see. Also, do you actually have a question here?

Answer 3

Thanks for your help