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Example code in “Functional Programming”

I don’t get this code. Why does the answer come out to be 20? If you pass the value from the first function to the second function, you don’t get an answer of 20! Can someone please explain this to me?

28th Jan 2019, 12:53 AM
Fred Jones
Fred Jones - avatar
5 Answers
+ 2
It does return 15 from the inner function: add_five(add_five(10)) == add_five(10+5) == add_five(15) == 15+5 == 20.
28th Jan 2019, 4:22 AM
Diego
Diego - avatar
+ 1
Are you talking about the code in the first slide? https://www.sololearn.com/learn/JUMP_LINK__&&__Python__&&__JUMP_LINK/2459/
28th Jan 2019, 1:56 AM
Diego
Diego - avatar
0
yes... shouldn’t this return 15 from the second funtion and then twice that, from the first function, for a total of 30? what am i getting wrong?
28th Jan 2019, 4:16 AM
Fred Jones
Fred Jones - avatar
0
got that... what about ‘apply_twice’ ? doesnt that function double the value returned from ‘add_five’? seems to me that that would be 30...
28th Jan 2019, 4:27 AM
Fred Jones
Fred Jones - avatar
0
You can do what's called substitution. apply_twice is defined as `func(func(arg))`. But then, when we call apply_twice, you can in your head substitute the arguments: `func` becomes `add_five` and `arg` becomes `10`. So `func(func(arg))` becomes `add_five(add_five(10))` and then we are at where Diego Acero started off.
28th Jan 2019, 4:54 AM
Schindlabua
Schindlabua - avatar