question python question print number of list

Question

list=[]
position = (3,3)
direction = [[0, 1]]
for x, y in direction:

if x >= 0 and x <= 7 and y >= 0 and y <=7:

list.append((position[0] + x, position[1] + y))

y += y
list.append((position[1] + x, position[1] + y))
y += y
list.append((position[1] + x, position[1] + y))

x += x
y += y

print(list)

I wan to print list of [[3, 4],[[3, 5],[[3, 6],[[3, 7]]
but the code print [[3, 4],[[3, 5],[[3, 7]]
I dont know why

Answer 1

Hope this helps
https://code.sololearn.com/cMCbOHDRpELR/?ref=app

Answer 2

1) You have appended something three times to the empty list, so there are 3 elements in list, not 4
2) Every time you doubled y, so y was: 1, 2, 4. You should use 'y += 1' to get 1, 2, 3 values.

Answer 3

l = []
position = (3,3)
direction = [[0, 1], [1, 1], [1, 0], [1, -1], [0, -1], [-1, -1], [-1, 0], [-1, 1]]

for x, y in direction :
if 0 <= x <= 7 and 0 <= y <= 7:
l.append([position[0] + x, position[1] + y])
y += 1
l.append([position[1] + x, position[1] + y])
y += 1

l.append([position[1] + x, position[1] + y])
y += 1

l.append([position[1] + x, position[1] + y])
print(l)

I want the code print all diretion until 7 of direction = [[0, 1], [1, 1], [1, 0], [1, -1], [0, -1], [-1, -1], [-1, 0], [-1, 1]]

but he print me th wrong position for example (3,3) with [[0, 1], is (3.4)