What is the problem in the code?

Question

swap two values using function by reference method ,
https://code.sololearn.com/csfvq2IfQ2K7/?ref=app

Answer 1

Nothing. Just in printf should be *a and *b for printing the values and not the addresses.

Answer 2

"but if I print in definition part then I don't have to use pointer a and b"

void swap(int*a,int*b)
{
int t;
t=*b;
*b=*a;
*a=t;
printf("after swapping\n%d and %d",a,b); // Output: 2358860 and 2358856 (decimal represemtation of where a and b point to)

printf("after swapping\n%d and %d", *a, *b); // Sample Output: 5 and 2 (for input 2 and 5)
}

So, they still need to get dereferenced through indirection (asterisk) operator.

Answer 3

ah I see thks ,but if I print in definition part then I don't have to use pointer a and b

Answer 4

yea I see