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+ 9

Why not after 23?

In my compiler it doesn't work when I input 23 and the higher value. #include<stdio.h> int main() { int t,n,i; double f; scanf("%d",&t); while(t>0) { f=1; scanf("%d",&n); for(i=1;i<=n;i++) { f=f*i; } printf("%.0lf\n",f); t--; } } Can you have that kind of experience before. What should I do?

17th Oct 2018, 12:42 PM
Coder
Coder - avatar
3 Answers
+ 3
Why not you just use the second one!! Actually I don't know the cause 😐
17th Oct 2018, 12:49 PM
Solo S
Solo S - avatar
+ 6
#include<stdio.h> int main() {int t,n,temp,j,m,a[200],i,x; scanf("%d",&t); while(t--) {m=1,a[0]=1,temp=0; scanf("%d",&n); for(i=1;i<=n;i++) { for(j=0;j<m;j++) {x=a[j]*i+temp; a[j]=x%10; temp=x/10; } while(temp>0) { a[m++]=temp%10; temp=temp/10; } } for(i=m-1;i>=0;i--) { printf("%d",a[i]); } printf("\n"); } return(0); } This code works. But why not that?
17th Oct 2018, 12:47 PM
Coder
Coder - avatar
+ 2
Can you upload the code to Code Playground and explain exactly what your input is and what doesn't work?
19th Oct 2018, 2:35 AM
Chris
Chris - avatar