How to declare multiple pointers in single code?

Question

In dynamic array and pointer allocation

Answer 1

In both C and C++, the * binds to the declarator, not the type specifier. In both languages, declarations are based on the types of expressions, not objects.

For example, suppose you have a pointer to an int named p, and you want to access the int value that p points to; you do so by dereferencing the pointer with the unary * operator, like so:

x = *p;
The type of the expression *p is int; thus, the declaration of p is

int *p;
This is true no matter how many pointers you declare within the same declaration statement; if q and r also need to be declared as pointers, then they also need to have the unary * as part of the declarator:

int *p, *q, *r;
because the expressions *q and *r have type int. It's an accident of C and C++ syntax that you can write T *p, T* p, or T * p; all of those declarations will be interpreted as T (*p).

This is why I'm not fond of the C++ style of declaring pointer and reference types as

T* p;
T& r;
because it implies an incorrect view of how C and C++ declaration syntax works, leading to the exact kind of confusion that you just experienced. However, I've written enough C++ to realize that there are times when that style does make the intent of the code clearer, especially when defining container types.

But it's still wrong.

Answer 2

thanks Savan i got exactly what i needed, i was kinda confused with the array one but now its great