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How these recursion works?

Hey can anyone explain to me how these recursion works? and what is the solution? i really have no idea thank a lot def charge= (h,k):        z = 0        outcome= 0              while z < h:               for i in range (z, k+1, 1):                     if i < 1:                        outcome = k                     elif i < 4:                                  outcome = outcome + i                     else:                                 outcome = outcome + h               z = z + 2        return outcome print charge(5,5)

14th Jul 2018, 10:28 AM
Sal
10 Answers
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Sal Because of the last expression in the while loop: z = z + 2 starting from z=0 (initialized before the while loop) running for z<h, where h=5 from the function call so when 6<5 it is false and it does not run anymore
15th Jul 2018, 2:01 PM
Matthias
Matthias - avatar
14th Jul 2018, 12:05 PM
Maninder $ingh
Maninder $ingh - avatar
+ 1
Matthias many thanks:)
14th Jul 2018, 2:53 PM
Sal
+ 1
Matthias aah now i get it. thank you:)
15th Jul 2018, 2:28 PM
Sal
0
This is not a recursion, since the function does not call itself. I don't really know if this has some real world source, but let's see how to get the value; z=0 range(0,6,1) i outcome 0 5 1 6 2 8 3 11 4 16 5 21 z=2 range(2,6,1) i outcome 2 23 3 26 4 31 5 36 z=4 range(4,6,1) i outcome 4 41 5 46 z=6 while loop terminated So it prints 46.
14th Jul 2018, 11:23 AM
Matthias
Matthias - avatar
0
hey Matthias, many thanks. now i understand. but can you explain how the otcome for z=0; i=4 is 16 ? And the outcome for z=2; i=5 is 26? thank you;)
14th Jul 2018, 11:59 AM
Sal
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Sal If i equals 4 or is greater than 4, you will get in the else branch. And there you add +h to your outcome. Here we have h=5, from the call charge(5,5) The other was a typo, it should be 36
14th Jul 2018, 12:11 PM
Matthias
Matthias - avatar
0
Matthias hello, i have a last question. how did you know that you have to repeat z for 0, 2 ,4 to 6?
15th Jul 2018, 1:59 PM
Sal
0
Glad to help :)
15th Jul 2018, 2:29 PM
Matthias
Matthias - avatar
0
Matthias i have a last question. really last question^^ def function (k): if k<2: return k else: return function(k-1)+function(k-2) n=8 z=function(n) print str (z) solution for this function: 8-1 + 8-2 = 13 7-1 + 5-2 = 9 6-1 + 3-2 = 6 so outcome is: 28 am i right?
15th Jul 2018, 3:14 PM
Sal