what is the C++ code doing?

Question

int* ptr = new int(27);
*ptr = 34;
...
delete ptr;

so
1. ptr is a pointer with a value 27
2. value at ptr is changed to 34
3. delete ptr

Answer 1

yeee! ... I'm abit confused about this part

*ptr=34;

I thought it's changing value at ptr to 34.when I do

cout << *ptr <<endln;

the value is 8327888