I need help

Question

write the code to display the smallest number stored in one - dimensional int array named orders . the array has five elements (10 , 20 , 18 , 25 , 9 ) . use the while statment

Answer 1

Assuming you know the basics as in how to declare the arrays - What you need to do now is to compare all arrays to find the smallest array:

E.g.

int smallest = 1000; // or any integer larger than all
if (smallest < array[0])
{
smallest = array[0];
}

The above segment of the code would only compare the first array to smallest, though.

Hence, you may use a loop and an integer variable to store and manipulate the corresponding array index so that all the arrays are compared.

E.g.

int smallest = 1000;

for (int i = 0; i < 5; i++)
{
// conditional statement here
// where smallest is compared to array[i]
}

However, you have stated that you need to use while loop. So I would leave it to you to figure that out, since this is probably an assignment question. :>

Answer 2

#include <iostream>
using namespace std;

int main() {
int orders[5]={10,20,18,9,25};

int small = orders[0];
int i =0;
while (i<5){
if (small>orders[i]){
small=orders[i];
}
i++;
}
cout<<small;

return 0;
}

this is the answer by while loop

Answer 3

first thx for help
second its not assessment