what is the regex for printing only the domain from a url?

Question

i have to do it with the use of regex only..
if i give the input as : http://www.google.com
The output should be :
www.google.com

Answer 1

import re
pattern = 'http[s]?://((?:[a-zA-Z]|[0-9]|[$-_@.&+]|[!*\(\),]|(?:%[0-9a-fA-F][0-9a-fA-F]))+)'
url ='https://www.sololearn.com/Discuss/1329933/?ref=app'
print(re.findall(pattern, url))
#Pattern Source: http://www.noah.org/wiki/RegEx_Python

Answer 2

Mert Yazıcı congratulations for level 16!

Answer 3

You could do it with string slicing:

x = "[e-mail]"
print(x[x.index("@") + 1::])

Answer 4

i have to do it with the use of regex only..
if i give the input as : http://www.google.com
The output should be :
www.google.com

Answer 5

https://stackoverflow.com/questions/29061521/regular-expression-to-match-only-domain-from-url

Answer 6

(?<=:\/\/)?([\w]+(?:\.\w+)+)
First group is the url.
http:// and www. are optional, weird top level domain names like .co.uk also pass this. File path is ignored.
Also put escapes before symbols if Python needs it, I don't know Python myself.