Why is the encrypt function outputing the memory location?

Question

here is the code:

from math import sqrt

class Code():
def __init__(self, text, key, t):
self.text = text
self.key = key
if t == "E":
self.encrypt(self.text, self.key)
elif t == "D":
self.decrypt(self.text, self.key)

def encrypt(self, text, key):
words = text.split(" ")
letters = []
encrypted_msg = []
for word in words:
letters.append(list(word))
for list1 in letters:
for letter in list1:
encrypted_msg.append((ord(letter)**2) + ord(key))
return encrypted_msg

def decrypt(self, msg, key):
int_words = " "
for number in msg:
int_words += str(chr(int(sqrt(number - ord(key)))))
return int_words

text = input("Input message:: ")
print ("........................................................")
print ("encrypting message")
print ("........................................................")
E_message = Code(text, "w", "E")
print (E_message)
print ("........................................................")
print ("decrypting message")
print ("....................

Answer 1

The problem is here.
E_message = Code(text, "w", "E")

This line creates Code class instance and the instance is saved to the E_message.
So this code shows the memory address of the object of Code.

Answer 2

Because your are printing a Code object that for default print his type and memory location... You want print the result of encrypt (and decrypt) function then you have not to do they in constructor and you have to edit ctor to store the key and encrypt/decrypt function for accept plain/encrypted text:

codeObj= Code(key)
encText= codeObj.encrypt(text)
plain= codeObj.decrypt(encText)

Answer 3

Oh! Thanks guys....it makes sense now.