Can someone explain in details?

Question

var a = 0
let b = ++a
let c = a++
print ("\(a) \(b) \(c)")

How come the result was 2 1 1 ?

Answer 1

var a = 0
let b = ++a
let c = a++
print ("\(a) \(b) \(c)")
a=0 then first pre increment a become 1 then post increment a become 2 when it is again called after c so value of a=2, b=1 ,c=1
b=++a=1 (here a is 0 then change after increment b=1)
c=a++=1(here a is 1 then post increment it remains 1 but when it called in print it becomes 2 so c=1 a=2)
print("\(a) \(b) \(c) ") so a=2 b=1 c=1

Answer 2

why cant u know ode

Answer 3

i am sorry my son did that