0
is it true?
#include <iostream> using namespace std; int main() { int a; int b; int p = a + b; cout<<"inter a number"; cin>>a/n; cout<<"inter another number"; cin>>b/n; cout<<p; return 0; }
7 Answers
+ 2
#include <iostream>
using namespace std;
int main() {
    int a;
    int b;
    cout<<"inter a number" << endl;
    cin >> a;
    cout<<"inter another number" << endl;
    cin >> b;
    
    cout << a+b;
    return 0;
}
I didn't know what the n is so  I removed "n".
+ 2
Programanta ludanto I'm guessing the /n is suppose to be a line break. Although it's implemented wrong. Amir Fall You need to do '\n' not /n.
+ 1
thanks đ
+ 1
What do you mean by is it true? This function won't output a boolean. And I doubt that'll even compile considering how many errors are in the code.
0
a/n and b/n are not lvalue
and what is "n"?
0
please right true âșâ€
0
#include <iostream>
using namespace std;
int main() {
    int a;
    int b;
    int p = a + b;
    cout<<"inter a number\n";
    cin>>a;
    cout<<"inter another number\n";
    cin>>b;
    cout<<p;
    return 0;
}



